2n^2-1600n+240000=0

Solution for 2n^2-1600n+240000=0 equation:

2n^2-1600n+240000=0

a = 2; b = -1600; c = +240000;
Δ = b2-4ac
Δ = -16002-4·2·240000
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{640000}=800$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1600)-800}{2*2}=\frac{800}{4}
=200
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1600)+800}{2*2}=\frac{2400}{4}
=600
$